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Is there a way to write this (python) so if a letter was input it wouldn't crash the program? It works if an out of range number and then a letter is
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![Programming In Python - #python #program to calculate #phone digits a=input("Enter phone number:- ") list=[] for i in range(0,10): res=a.count(str(i),0,10) list.append(str(i) + " occur "+ str(res)+" times") for i in range(0,10): print(list[i]) #](https://lookaside.fbsbx.com/lookaside/crawler/media/?media_id=330378347584769 "Programming In Python - #python #program to calculate #phone digits a=input(\"Enter phone number:- \") list=[] for i in range(0,10): res=a.count(str(i),0,10) list.append(str(i) + \" occur \"+ str(res)+\" times\") for i in range(0,10): print(list[i]) #")
Programming In Python - #python #program to calculate #phone digits a=input("Enter phone number:- ") list=[] for i in range(0,10): res=a.count(str(i),0,10) list.append(str(i) + " occur "+ str(res)+" times") for i in range(0,10): print(list[i]) #
Python range() Function Explained with Examples
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Python range() Function Explained with Examples
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SOLVED: in python please 5.17 LAB: Output range with increment of 10 Write a program whose input is two integers.Output the first integer and subsequent increments of 10 as long as the
